A-LevelMathematicsMechanics9709/52 · May/June 2019 · Q68 Marks
A particle is projected with speed 15 m s⁻¹ at an angle of θ° above the horizontal. At the instant 4 s after projection the speed of the particle is 30 m s⁻¹.
- (i)Find θ.[4]
- (ii)Show that at the instant 4 s after projection the particle is 33.75 m below the level of the point of projection and find the direction of motion at this instant.[4]
Mark scheme
Marking points from the official mark scheme (May/June 2019). The mark or mark type is shown in brackets.
- [B1] Use horizontal and vertical motion
- [M1] Use Pythagoras's theorem
- [M1] Attempt to solve for θ
- [A1]
- [B1]
- [M1] Allow h not replaced
- [M1] Attempt to eliminate h and attempt to solve for θ
- [A1]
- [M1] Use vertical motion. Allow their θ for first M1
- [A1] AG
- [M1] Use trigonometry of a right angled triangle
- [A1] α = 71.4° below the horizontal
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