A-LevelMathematicsVectors9709/12 · Feb/Mar 2019 · Q57 Marks
Two vectors, u and v, are such that u = (2) (q) (6) and v = (8) (q-1) (q²-7) , where q is a constant.
- (i)Find the values of q for which u is perpendicular to v.[3]
- (ii)Find the angle between u and v when q = 0.[4]
Mark scheme
Marking points from the official mark scheme (Feb/Mar 2019). The mark or mark type is shown in brackets.
- [B1] u.v = 8q + 2q − 2 + 6q² – 42
- [M1] 6q² +10q-44 = 0 oe
- [A1] q = 2, -11/3
- [M1] Correct method for scalar product
- [M1] Prod of mods. At least one methodically correct.
- [M1] All linked correctly and inverse cos used correctly
- [A1] θ=130.7° or 2.28(05) rads
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