A bus moves in a straight line between two bus stops. The bus starts from rest and accelerates at 2.1 m s⁻² for 5 s. The bus then travels for 24 s at constant speed and finally slows down, with a constant deceleration, stopping in a further 6 s. Sketch a velocity-time graph for the motion and hence find the distance between the two bus stops.
- Sketch a velocity-time graph for the motion and hence find the distance between the two bus stops.[5]
Mark scheme
Marking points from the official mark scheme (May/June 2019). The mark or mark type is shown in brackets.
- [B1] Trapezium. Includes (0,0) and (...,0)
- [B1] Correct trapezium with key time values (t = 0), t = 5, t = 29, t = 35
- [B1] Vmax = 2.1 × 5 = 10.5 ms⁻¹
- [M1] Use of area property to find distance: [½ x (24 +35) × 10.5] or [½ × 5 × 10.5 + 24 × 10.5 + ½ × 6 × 10.5]
- [A1] 309.75 m or 310 m
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