Skip to main content
A-LevelMathematicsMechanics9709/52 · Feb/Mar 2018 · Q25 Marks

An object is projected with speed 15 m s¯¹ at an angle of 35° above the horizontal from a point on horizontal ground. Find the speed and direction of motion of the object at time 2 s after the instant of projection.

  1. An object is projected with speed 15 m s¯¹ at an angle of 35° above the horizontal from a point on horizontal ground. Find the speed and direction of motion of the object at time 2 s after the instant of projection.[5]

Mark scheme

Marking points from the official mark scheme (Feb/Mar 2018). The mark or mark type is shown in brackets.

  1. [B1] u = 15cos35 ( = 12.287) Use horizontal motion
  2. [B1] v = 15sin35 - 2g ( = -11.396) Use vertical motion
  3. [M1] V = √(12.2872 + 11.396²) OR tanθ = ±11.396 / 12.287
  4. [A1] V = 16.8 m s⁻¹
  5. [A1] θ = 42.8° below the horizontal

Write your answer and get it marked

On Oracle Prep you can write or photograph your own answer and have it marked by AI against this mark scheme, with feedback on what you missed.

Sign up free →

About this question

Topic
Mechanics, A-Level Mathematics (syllabus 9709). Structured question, 5 marks.
Source
A-Level Mathematics, Feb/Mar 2018 Paper 5 Variant 2, question 2.

Questions and mark schemes are from past examination papers and remain the copyright of the exam board. How Oracle Prep builds its content

Related Mathematics questions

© 2026 Oracle Prep