A particle P moves in a straight line starting from a point O. At time t s after leaving O, the velocity, v m s⁻¹, of P is given by v = (2t – 5)³.
- (i)Find the values of t when the acceleration of P is 54 m s⁻².[3]
- (ii)Find an expression for the displacement of P from O at time t s.[3]
Mark scheme
Marking points from the official mark scheme (May/June 2017). The mark or mark type is shown in brackets.
- *M1 Uses a = dv/dt
- DM1 Solves for t
- A1 t = 1,4
- *M1 Uses s = ∫ v dt
- DM1 Uses s = 0 at t = 0
- A1 s = (2t-5)⁴/8 - 625/8
- *M1 Uses a = dv/dt
- DM1 Solves for t
- A1 t = 1,4
- *M1 Uses s = ∫ v dt
- DM1 Uses s = 0 at t=0 (may be implied)
- A1 s = 2t⁴ - 20t³ + 75t² – 125t
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