Find ∫ (2 cos θ – 3)(cos θ + 1) dθ.
- (a)Find ∫ (2 cos θ – 3)(cos θ + 1) dθ.[4]
- (b)(i)Find ∫ (4/(2x+1) + 1/(2x)) dx.[2]
- (b)(ii)Hence find ∫ from 1 to 4 of (4/(2x+1) + 1/(2x)) dx, giving your answer in the form ln k.[3]
Mark scheme
Marking points from the official mark scheme (May/June 2017). The mark or mark type is shown in brackets.
- [B1] Obtain ∫(2cos²θ-cosθ-3)dθ
- [M1] Attempt use of identity to obtain integrand involving cos 2θ and cosθ
- [M1] Integrate to obtain form k₁ sin 2θ+ k₂ sin θ+ k₃θ for non-zero constants
- [A1] Obtain 1/2 sin 2θ – sin θ – 2θ + c
- [M1] Integrate to obtain form k₁ ln(2x+1)+ k₂ ln(x) or k₁ ln(2x+1)+k₂ ln(2x)
- [A1] Obtain 2ln(2x+1)+1/2lnx or 2ln(2x+1)+1/2ln(2x)
- [M1] Use relevant logarithm power law for expression obtained from application of limits
- [M1] Use relevant logarithm addition / subtraction laws
- [A1] Obtain ln18
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