Relative to the origin O, the position vectors of the points A, B and C are given by `OA = (2 5)`, `OB = (4 3)`, `OC = (10 6)`. The point D is such that ABCD is a parallelogram.
- (i)Find angle ABC.[6]
- (ii)Find the position vector of D.[2]
Mark scheme
Marking points from the official mark scheme (May/June 2011). The mark or mark type is shown in brackets.
- [6] (i) BA.BC or AB.CB; B1 Correct two vectors for angle ABC.; BA = (-2 2); BC = (6 -3); M1 Correct method for one of the sides.; BA.BC = -8; M1 Correct use for any pair of vectors.; |BA| = √((-2)²+2²) = √8; |BC| = √(6²+(-3)²) = √45; M1 Correct method for moduli.; cos θ = (-8) / (√8 * √45); M1 A1 All linked correctly. co (67.6° usually gets 4/6); → θ = 112.4° or 1.96 radians
- [2] (ii) OD = OA + AD = OA + BC; M1 Correct method. (allow for d = a + b − c or for d = a + c − b or for d = b + c − a); A1√ Al for his BC.; → OD = (8 8)
Write your answer and get it marked
On Oracle Prep you can write or photograph your own answer and have it marked by AI against this mark scheme, with feedback on what you missed.
Sign up free →