The function f is defined by f(x) = −3x² + 2 for x ≤ −1.
- (a)State the range of f.[1]
- (b)Find an expression for f⁻¹(x).[3]
- (c)The function g is defined by g(x) = −x² − 1 for x ≤ −1. Solve the equation fg(x) – gf(x) + 8 = 0.[5]
Mark scheme
Marking points from the official mark scheme (Feb/Mar 2023). The mark or mark type is shown in brackets.
- [B1] [y]≤-1 Accept for f(x)<-1, -∞<y<−1, (-∞,-1]. Do not accept x≤−1.
- [M1] y = −3x² +2 rearranged to 3x² = 2−y, leading to x² = (2-y)/3 or y² = (2-x)/3
- [A1 A1] x = -√( (2-y)/3 ) → [f⁻¹(x)] = -√( (2-x)/3 ) Al for minus, Al for √( (2-x)/3 ), allow √( (x-2)/-3 )
- [M1] fg(x) = -3(-x²-1)² +2 SOI expect -3x⁴-6x²-1.
- [M1] gf(x) = -(-3x²+2)² -1 SOI expect –9x⁴ +12x² -5.
- [A1] fg(x)- gf(x)+8=0 leading to 6x⁴ -18x² +12 [=0] OE
- [M1] [6](x²-1)(x²-2) [=0] or formula or completion of the square Solving a 3-term quadratic equation in x² must be seen.
- [A1] x=-1,-√2 only these two solutions Allow -1, -1.41[4] Answers only SC B1.
Write your answer and get it marked
On Oracle Prep you can write or photograph your own answer and have it marked by AI against this mark scheme, with feedback on what you missed.
Sign up free →