The random variable X has a normal distribution with mean 10 and standard deviation 3. The independent random variable Y has a Poisson distribution with mean 4.
- (a)Find the standard deviation of X + Y.[3]
- (b)Find the standard deviation of 5X - Y.[3]
Mark scheme
Marking points from the official mark scheme (Oct/Nov 2025). The mark or mark type is shown in brackets.
- [1] (a) Var(Y) = 4
- [1] (a) Var(X + Y) = 3² + ‘4’
- [1] (a) sd of X + Y = √13 = 3.61
- [1] (b) Var(5X) = 5² × 3²
- [1] (b) Var(5X - Y) = Var(5X) + Var(Y) = “5² × 3²” + “4”
- [1] (b) sd of 5X - Y = √229 or 15.1 (3 sf)
Write your answer and get it marked
On Oracle Prep you can write or photograph your own answer and have it marked by AI against this mark scheme, with feedback on what you missed.
Sign up free →