A-LevelMathematicsDifferentiation9709/22 · Feb/Mar 2020 · Q46 Marks
A curve has equation 3x² - y² – 4 ln(2y + 3) = 26. Find the equation of the tangent to the curve at the point (3, −1).
- A curve has equation 3x² - y² – 4 ln(2y + 3) = 26. Find the equation of the tangent to the curve at the point (3, −1).[6]
Mark scheme
Marking points from the official mark scheme (Feb/Mar 2020). The mark or mark type is shown in brackets.
- Differentiate -y² to obtain -2y(dy/dx)
- Differentiate -4ln(2y+3) to obtain -8/(2y+3) (dy/dx)
- Attempt differentiation of all terms Dependent on appearance of at least one dy/dx
- Substitute x = 3, y=-1 to find numerical value of dy/dx
- Obtain dy/dx = 3
- Obtain equation y = 3x-10 OE
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