With respect to the origin O, the points A, B, C and D have position vectors given by OA = (1 5 3), OB = (0 4 1), OC = (1 -3 1) and OD = (3 -5 4). The line m passes through the points A and B.
- (a)Find a vector equation for m.[2]
- (b)Find the position vector of the point of intersection of m and the line passing through the points C and D.[4]
- (c)Find the position vector of the foot of the perpendicular from C to m.[4]
Mark scheme
Marking points from the official mark scheme (Oct/Nov 2025). The mark or mark type is shown in brackets.
- [M1] Carry out a correct method for finding a vector equation for m
- [A1] Obtain r = (1 5 3) + λ( -1 -1 -2 )
- [B1] Express general point of the second line in component form, i.e. (1 + 2μ, −3 – 2μ, 1 + 3μ)
- [M1] Equate at least two pairs of corresponding components and solve for λ or for μ
- [A1] Obtain λ = −4 or μ = −2
- [A1] Obtain position vector of point of intersection is (-3 1 -5)
- [B1] Find CP for a general point P on m, e.g. (0 8+λ 2+2λ)
- [M1] Calculate scalar product of CP and a direction vector for m and equate the result to zero
- [A1] Obtain λ = -2
- [A1] Obtain answer (-1 3 -1)
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