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A-LevelMathematicsMechanics9709/43 · Oct/Nov 2024 · Q14 Marks

An athlete has mass mkg. The athlete runs along a horizontal road against a constant resistance force of magnitude 24 N. The total work done by the athlete in increasing his speed from 5ms⁻¹ to 6ms⁻¹ while running a distance of 50 metres is 1541 J.

  1. (a)Find the value of m.[4]

Mark scheme

Marking points from the official mark scheme (Oct/Nov 2024). The mark or mark type is shown in brackets.

  1. [B1] For either correct. Do not allow 1/2*m*(6-5)^2. Note: Difference = 1/2*m*11.
  2. [B1] Do not allow if errors such as e.g. (m-24)*50.
  3. [M1] Attempt at work energy equation with 4 relevant terms; dimensionally correct. Allow sign errors. M0 for 1/2*m*(6-5)^2.
  4. [A1]
  5. [SCB1] From 6^2 = 5^2 + 2*a*50 SOI.
  6. [SCB1] From 1541/50 - 24 = m*0.11 or 30.82-24=m*0.11.

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About this question

Topic
Mechanics, A-Level Mathematics (syllabus 9709). Structured question, 4 marks.
Source
A-Level Mathematics, Oct/Nov 2024 Paper 4 Variant 3, question 1.

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