An athlete has mass mkg. The athlete runs along a horizontal road against a constant resistance force of magnitude 24 N. The total work done by the athlete in increasing his speed from 5ms⁻¹ to 6ms⁻¹ while running a distance of 50 metres is 1541 J.
- (a)Find the value of m.[4]
Mark scheme
Marking points from the official mark scheme (Oct/Nov 2024). The mark or mark type is shown in brackets.
- [B1] For either correct. Do not allow 1/2*m*(6-5)^2. Note: Difference = 1/2*m*11.
- [B1] Do not allow if errors such as e.g. (m-24)*50.
- [M1] Attempt at work energy equation with 4 relevant terms; dimensionally correct. Allow sign errors. M0 for 1/2*m*(6-5)^2.
- [A1]
- [SCB1] From 6^2 = 5^2 + 2*a*50 SOI.
- [SCB1] From 1541/50 - 24 = m*0.11 or 30.82-24=m*0.11.
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