Show that sin 2θ cot θ – cos 2θ = 1.
- (a)Show that sin 2θ cot θ – cos 2θ = 1.[3]
- (b)Hence find the exact value of sin 1/6π cot 1/6π.[2]
- (c)Find the smallest positive value of θ (in radians) satisfying the equation sin 2θ cot θ – 3 cos 2θ = 1.[2]
Mark scheme
Marking points from the official mark scheme (Feb/Mar 2022). The mark or mark type is shown in brackets.
- [B1] Use at least two of sin 2θ = 2 sin θ cos θ, cos 2θ = cos² θ – sin² θ, cot θ = cos θ/sin θ [OE]
- [M1] Express LHS in terms of sin θ and cos θ only and attempt valid simplification
- [A1] Obtain cos² θ + sin² θ or equivalent and hence 1 [AG – necessary detail needed]
- [M1] Substitute θ = π/6 and show or imply sin(π/3)cot(π/6) = 1 + cos(π/3)
- [A1] Obtain 1 + √3 or exact equivalent
- [M1] Use the identity from part (a) to obtain -2 cos 2θ = 0 or equivalent [Or alternative starting again, using valid simplification and reaching single trigonometric function.]
- [A1] Obtain θ = π/4
Write your answer and get it marked
On Oracle Prep you can write or photograph your own answer and have it marked by AI against this mark scheme, with feedback on what you missed.
Sign up free →