Hazeem repeatedly throws two ordinary fair 6-sided dice at the same time. On each occasion, the score is the sum of the two numbers that she obtains.
- (a)Find the probability that it takes exactly 5 throws of the two dice for Hazeem to obtain a score of 8 or more.[2]
- (b)Find the probability that it takes no more than 4 throws of the two dice for Hazeem to obtain a score of 8 or more.[2]
- (c)For 8 randomly chosen throws of the two dice, find the probability that Hazeem obtains a score of 8 or more on fewer than 3 occasions.[3]
Mark scheme
Marking points from the official mark scheme (Oct/Nov 2023). The mark or mark type is shown in brackets.
- [M1] (1-p)ʳ⁻¹xp, 0<p<1
- [A1] 0.0482454... to at least 3SF.
- [M1] 1-bʳ, b = their (1–p) in 2(a) or correct; r = 4, 5.
- [A1] 0.884211... to at least 3SF.
- [M1] p + p(1-p) + p(1 –p)² + p(1 –p)³ [+p(1-p)⁴)] FT from 2(a) or correct.
- [A1] 0.884211... to at least 3SF.
- [M1] One term ⁸Cₓ(q)ˣ(1-q)⁸⁻ˣ, 0<q<1, x≠0,8.
- [A1 FT] Correct expression, accept unsimplified, no terms omitted leading to final answer. FT only with unsimplified expression.
- [B1] 0.2815 ≤ q < 0.282
Write your answer and get it marked
On Oracle Prep you can write or photograph your own answer and have it marked by AI against this mark scheme, with feedback on what you missed.
Sign up free →