A block of mass 15kg slides down a line of greatest slope of an inclined plane. The top of the plane is at a vertical height of 1.6m above the level of the bottom of the plane. The speed of the block at the top of the plane is 2ms⁻¹ and the speed of the block at the bottom of the plane is 4 ms⁻¹. Find the work done against the resistance to motion of the block.
- Find the work done against the resistance to motion of the block.[4]
Mark scheme
Marking points from the official mark scheme (Oct/Nov 2023). The mark or mark type is shown in brackets.
- [B1] For KE at top or bottom. Need not be evaluated. ½ ×15×(4–2)² is B0.
- [B1] For PE change. Need not be evaluated.
- [M1] Attempt at work energy equation; 4 relevant terms; dimensionally correct; allow sign errors. ½ ×15×(4–2)² is M0. If W = F times a numerical distance seen, then M0.
- [A1]
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