A particle moves in a straight line. It starts from rest at a fixed point O on the line. Its acceleration at time t s after leaving O is a m s⁻², where a = 0.4t³ – 4.8t².
- (i)Show that, in the subsequent motion, the acceleration of the particle when it comes to instantaneous rest is 16 m s⁻².[6]
- (ii)Find the displacement of the particle from O at t = 5.[3]
Mark scheme
Marking points from the official mark scheme (Feb/Mar 2019). The mark or mark type is shown in brackets.
- [M1] Attempt to integrate a [∫ 0.4t³ - 4.8t² dt]
- [A1] v = 0.1t⁴ - 3.2t³ (+c)
- [DM1] Attempt to solve v = 0, and reach the form tᵃˡᵇ = k [v = 0 → 0.1t⁴ - 3.2t³ = 0]
- [M1] Attempt to solve an equation of the form tᵃˡᵇ = k [t² = 32]
- [A1] t = 4
- [B1] a = 16 m s⁻²
- [M1] Attempt to integrate v [s = [0.1t⁴ - 3.2t³ dt]]
- [A1] Correct integration. Displacement = 0.02t⁵ - 1.28t⁴
- [A1] Displacement = –9.05 m (–9.05417...)
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