A game is played with an ordinary fair 6-sided die. A player throws the die once. If the result is 2, 3, 4 or 5, that result is the player's score and the player does not throw the die again. If the result is 1 or 6, the player throws the die a second time and the player's score is the sum of the two numbers from the two throws.
- (a)Draw a fully labelled tree diagram to represent this information.[2]
- (b)Events A and B are defined as follows. A: the player's score is 5, 6, 7, 8 or 9 B: the player has two throws Show that P(A) = 1/3.[3]
- (c)Determine whether or not events A and B are independent.[2]
- (d)Find P(B | A').[3]
This question uses a diagram from the original paper, which isn't shown here. Open the full paper from the past papers archive to see it.
Mark scheme
Marking points from the official mark scheme (Oct/Nov 2022). The mark or mark type is shown in brackets.
- [B1] 1st throw fully correct with probabilities and outcomes identified. (Probabilities all 1/6 and outcomes (1,2,3,4,5,6) on branches).
- [B1] 2nd throw fully correct with probabilities and outcomes identified. (Probabilities all (all) 1/6 and outcomes (1,2,3,4,5,6) on branches).
- [B1] P(5) or P(7) identified and correct unsimplified, accept if supported by correct scenarios shown or from tree diagram .
- [M1] Adding only the values from 5 correct scenarios.
- [A1] Scenarios identified (may be on tree diagram in 5(a)), all probabilities seen, WWW AG.
- [M1] Both identified and evaluated, consistent with their tree diagram or correct.
- [A1] P(A) × P(B) seen and evaluated, all notation present and correct. Correct conclusion WWW.
- [B1] their 6/36 oe as numerator of a fraction.
- [M1] their 6/36 / their (1 - 1/3) or correct seen, consistent with their tree diagram.
- [A1] 1/4, 0.25
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