A bus moves from rest with constant acceleration for 12 s. It then moves with constant speed for 30 s before decelerating uniformly to rest in a further 6 s. The total distance travelled is 585 m.
- (a)Find the constant speed of the bus.[2]
- (b)Find the magnitude of the deceleration.[1]
Mark scheme
Marking points from the official mark scheme (Oct/Nov 2021). The mark or mark type is shown in brackets.
- [M1] Use of constant acceleration equations or a v-t graph. Complete method to set up an equation in V using constant acceleration equations or correct area formula in v-t graph.
- [A1] Speed of the bus = 15 ms⁻¹. Must be positive.
- [B1 FT] Magnitude of deceleration = 2.5. OE. Do not allow a = -2.5.
Write your answer and get it marked
On Oracle Prep you can write or photograph your own answer and have it marked by AI against this mark scheme, with feedback on what you missed.
Sign up free →