The diagram shows the curve y = √x cos x, for 0 < x < ¾π, and its minimum point M, where x = a. The shaded region between the curve and the x-axis is denoted by R. [Figure X.X]
- (a)Show that a satisfies the equation tan a = 1 2a [3]
- (b)The sequence of values given by the iterative formula a_n+1 = π + tan⁻¹(1/(2a_n)), with initial value x_1 = 3, converges to a. Use this formula to determine a correct to 2 decimal places. Give the result of each iteration to 4 decimal places.[3]
- (c)Find the volume of the solid obtained when the region R is rotated completely about the x-axis. Give your answer in terms of π.[6]
This question uses a diagram from the original paper, which isn't shown here. Open the full paper from the past papers archive to see it.
Mark scheme
Marking points from the official mark scheme (Oct/Nov 2020). The mark or mark type is shown in brackets.
- [M1] Use correct product rule
- [A1] Obtain correct derivative in any form e.g. dy/dx = (1/(2√x)) cosx - √x sinx
- [A1] Equate derivative to zero and obtain tan a = 1/(2a)
- [M1] Use the iterative process correctly at least once (get one value and go on to use it in a second use of the formula)
- [A1] Show sufficient iterations to at least 4 d.p. to justify 3.29, or show there is a sign change in the interval (3.285, 3.295)
- [A1] Obtain final answer 3.29
- [B1] State or imply the indefinite integral for the volume is π ∫(√x cosx)² dx [If π omitted, or 2π or π/2 used, give B0 and follow through. 4/6 available]
- [*M1] Use correct cos 2A formula, commence integration by parts and reach x(ax+b sin 2x) ± ∫ ax+b sin 2x dx
- [A1] Obtain x(x/2 + (1/4)sin 2x) - ∫(x/2 + (1/4)sin 2x) dx, or equivalent
- [A1] Complete integration and obtain (1/4)x² + (1/4)x sin 2x + (1/8)cos 2x
- [DM1] Substitute limits x = 0 and x = π/2, having integrated twice
- [A1] Obtain answer π(π²/16 - 1/4), or exact equivalent
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