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A-LevelMathematicsDifferentiation9709/32 · Oct/Nov 2020 · Q57 Marks

The diagram shows the curve with parametric equations x = tan θ, y = cos² θ, for −π < θ < π. [Figure X.X]

  1. (a)Show that the gradient of the curve at the point with parameter θ is −2 sin θ cos³ θ.[3]
  2. (b)Find the exact value of the x-coordinate of P.[4]

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Mark scheme

Marking points from the official mark scheme (Oct/Nov 2020). The mark or mark type is shown in brackets.

  1. [B1] State dx/dθ = sec² θ or dy/dθ = -2 sin θ cos θ
  2. [M1] Use dy/dx = (dy/dθ) / (dx/dθ)
  3. [A1] Obtain dy/dx = -2 sin θ cos³ θ from correct working
  4. [M1] Use correct product rule to obtain d/dθ (±2 cos³ θ sin θ)
  5. [A1] Obtain correct derivative in any form (e.g. ±(-2cos⁴θ + 6sin²θcos²θ))
  6. [A1] Equate derivative to zero and obtain an equation in one trig ratio (e.g. 3 tan²θ=1, or 4sin²θ=1 or 4 cos²θ=3)
  7. [A1] Obtain answer x = 1/√3 or -1/√3

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About this question

Topic
Differentiation, A-Level Mathematics (syllabus 9709). Structured question, 7 marks.
Source
A-Level Mathematics, Oct/Nov 2020 Paper 3 Variant 2, question 5.

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