Find ∫ (8/(4x+1) + 8/cos²(4x+1)) dx.
- (a)Find ∫ (8/(4x+1) + 8/cos²(4x+1)) dx.[4]
- (b)It is given that ∫[0 to π/4] (3 + 4 cos²(½x) + k sin 2x) dx = 10. Find the exact value of the constant k.[6]
Mark scheme
Marking points from the official mark scheme (Oct/Nov 2020). The mark or mark type is shown in brackets.
- [1] Express 8/cos²(4x+1) as 8sec²(4x+1)
- [1] Integrate to obtain the form aln(4x+1)
- [1] Integrate to obtain btan(4x+1)
- [1] Obtain 2ln|4x+1|+2tan(4x+1)+c Condone use of brackets rather than modulus signs
- [1] Express 4cos²(1/2x) in the form p+qcosx For constants where pq ≠ 0
- [1] Obtain correct 2+2cosx
- [1] Integrate to obtain form px+qsinx+rcos2x For constants where pqr ≠ 0
- [1] Obtain correct 5x+2sinx-k/2cos2x Allow 3x + 2x in place of 5x
- [1] Apply limits correctly, equate to 10 and solve for k
- [1] Obtain k = 8-5/2π CWO
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