The diagram shows part of the curve y = 2/(3-2x)² - x and its minimum point M, which lies on the x-axis. [Figure 10.1]
- (a)Find expressions for dy/dx, d²y/dx² and ∫y dx.[6]
- (b)Find, by calculation, the x-coordinate of M.[2]
- (c)Find the area of the shaded region bounded by the curve and the coordinate axes.[2]
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Mark scheme
Marking points from the official mark scheme (Oct/Nov 2020). The mark or mark type is shown in brackets.
- [B2, 1, 0] B2 for all three elements correct, B1 for two elements correct, B0 for only one or no elements correct.
- [B1FT] FT providing their bracket is to a negative power
- [B1] 1/(3-2x)
- [B1] -x²/2
- [B1] + c
- [M1] Setting their 2-term differential to 0 and attempts to solve as far as x =
- [A1] x = ½
- [M1] Using their integral, their positive x limit from part (b) and 0 correctly.
- [A1] 1/24
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