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A-LevelMathematicsProbability and statistics9709/62 · Feb/Mar 2020 · Q38 Marks

In the past, the mean time taken by Freda for a particular daily journey was 39.2 minutes. Following the introduction of a one-way system, Freda wishes to test whether the mean time for the journey has decreased. She notes the times, t minutes, for 40 randomly chosen journeys and summarises the results as follows. n = 40 Σt = 1504 Σt² = 57760

  1. (a)Calculate unbiased estimates of the population mean and variance of the new journey time.[3]
  2. (b)Test, at the 5% significance level, whether the population mean time has decreased.[5]

Mark scheme

Marking points from the official mark scheme (Feb/Mar 2020). The mark or mark type is shown in brackets.

  1. [B1] est (µ) = 1504/40 = 37.6 or 188/5
  2. [M1] est (σ²) = [1/(40-1)] * [57760 - (1504^2)/40]; Correct substitution in any correct formula [57760 - 1504^2/40]
  3. [A1] = 31.(0) (3 sf); Accept 2016/65 or 31 1/65
  4. [B1] H₀: Pop mean (or µ) = 39.2; H₁: Pop mean (or µ) < 39.2; Both. Not just 'mean'
  5. [M1] ('37.6' - 39.2) / sqrt('31.0154' / 40); Allow use of biased variance (30.2), must have √40
  6. [A1] = -1.817; SC FT use of biased = -1.840 for A1
  7. [M1] '1.817' > 1.645 OE; Valid comparison 'their 1.817' with 1.645 or valid area comparison 0.0346 < 0.05 OE
  8. [A1FT] There is evidence that mean time has decreased; FT their 1.817; in context, not definite, no contradictions; SC For 2 tail test: H₁: µ ≠ 39.2 and comp 1.96, max B0M1A1M1A0 (no FT for final mark)

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About this question

Topic
Probability and statistics, A-Level Mathematics (syllabus 9709). Structured question, 8 marks.
Source
A-Level Mathematics, Feb/Mar 2020 Paper 6 Variant 2, question 3.

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