In Quarendon, 66% of households are satisfied with the speed of their wifi connection.
- (i)Find the probability that, out of 10 households chosen at random in Quarendon, at least 8 are satisfied with the speed of their wifi connection.[3]
- (ii)A random sample of 150 households in Quarendon is chosen. Use a suitable approximation to find the probability that more than 84 are satisfied with the speed of their wifi connection.[5]
Mark scheme
Marking points from the official mark scheme (Oct/Nov 2019). The mark or mark type is shown in brackets.
- [M1] Correct binomial term, ¹⁰Ca 0.66º(1−0.66)ᵇ a+b=10, 0<a,b<10
- [A1] Correct unsimplified expression
- [B1] CAO 0.284
- [B1] Accept evaluated or unsimplified μ, σ² numerical expressions, condone σ= √33.66 = 5.8017 or 5.802 CAO np = 0.66×150 = 99 npq = 0.66×(1-0.66)×150 = 33.66
- [M1] + Standardise, (x - their 99) / (√their 33.66) condone o², x a value
- [M1] 84.5 or 83.5 used in their standardisation formula
- [M1] Correct final area
- [A1] Final answer (accept 0.9938) SC if no standardisation formula seen, B2 P(Z > -2.499) = 0.994
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