Two particles A and B move in the same vertical line. Particle A is projected vertically upwards from the ground with speed 20m s⁻¹. One second later particle B is dropped from rest from a height of 40 m.
- (i)Find the height above the ground at which the two particles collide.[4]
- (ii)Find the difference in the speeds of the two particles at the instant when the collision occurs.[3]
Mark scheme
Marking points from the official mark scheme (Oct/Nov 2019). The mark or mark type is shown in brackets.
- [B1] OE
- [M1] Set up an equation using their hA, their hB and 40
- [DM1] Solve for t and attempt to find the height at collision.
- [A1] T = 2.5 and height at collision = 8.75 m
- [M1] Use of their t or their h < 20 from 5(i) in a constant acceleration formula which would lead to finding VA
- [M1] Use of their t + 1 or their 40 – h from 5(i) in a constant acceleration formula which would lead to finding VB
- [A1] Difference = 10 ms⁻¹ CWO
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