The planes m and n have equations 3x + y − 2z = 10 and x − 2y + 2z = 5 respectively. The line l has equation r = 4i + 2j + k + λ(i + j + 2k).
- (i)Show that l is parallel to m.[3]
- (ii)Calculate the acute angle between the planes m and n.[3]
- (iii)A point P lies on the line l. The perpendicular distance of P from the plane n is equal to 2. Find the position vectors of the two possible positions of P.[4]
Mark scheme
Marking points from the official mark scheme (Oct/Nov 2018). The mark or mark type is shown in brackets.
- [M1] (i) EITHER: Expand scalar product of a normal to m and a direction vector of l
- [A1] (i) Verify scalar product is zero
- [A1] (i) Verify that one point of l does not lie in the plane
- [M1] (i) OR: Substitute coordinates of a general point of l in the equation of the plane m
- [A1] (i) Obtain correct equation in λ in any form
- [A1] (i) Verify that the equation is not satisfied for any value of λ
- [M1] (ii) Use correct method to evaluate a scalar product of normal vectors to m and n
- [M1] (ii) Using the correct process for the moduli, divide the scalar product by the product of the moduli and evaluate the inverse cosine of the result
- [A1] (ii) Obtain answer 74.5° or 1.30 radians
- [M1] (iii) EITHER: Using the components of a general point P of l form an equation in λ by equating the perpendicular distance from n to 2
- [M1] (iii) OR: Take a point Q on l, e.g. (5, 3, 3) and form an equation in λ by equating the length of the projection of QP onto a normal to plane n to 2
- [A1] (iii) Obtain a correct modular or non-modular equation in any form
- [A1] (iii) Solve for λ and obtain a position vector for P, e.g. 7i + 5j + 7k from λ = 3
- [A1] (iii) Obtain position vector of the second point, e.g. 3i + j – k from λ = –1
Write your answer and get it marked
On Oracle Prep you can write or photograph your own answer and have it marked by AI against this mark scheme, with feedback on what you missed.
Sign up free →