The diagram shows part of the curve y = x(9 – x²) and the line y = 5x, intersecting at the origin O and the point R. Point P lies on the line y = 5x between O and R and the x-coordinate of P is t. Point Q lies on the curve and PQ is parallel to the y-axis.
- (i)Express the length of PQ in terms of t, simplifying your answer.[2]
- (ii)Given that t can vary, find the maximum value of the length of PQ.[3]
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Mark scheme
Marking points from the official mark scheme (Oct/Nov 2018). The mark or mark type is shown in brackets.
- [B1] P is (t, 5t)
- [B1] Q is (t, t(9 – t²)) → 4t – t³
- [B1FT] d(PQ)/dt = 4 - 3t²
- [M1] = 0 → t = ±√(2/3)
- [A1] → Maximum PQ = 16/(3√3) or 16√3/9
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