(a) Find the number of different 3-digit numbers greater than 300 that can be made from the digits 1, 2, 3, 4, 6, 8 if (b) A team of 5 is chosen from 6 boys and 4 girls. Find the number of ways the team can be chosen if
- (a)(i)no digit can be repeated,[3]
- (a)(ii)a digit can be repeated and the number made is even.[3]
- (b)(i)there are no restrictions,[1]
- (b)(ii)the team contains more boys than girls.[3]
Mark scheme
Marking points from the official mark scheme (Oct/Nov 2017). The mark or mark type is shown in brackets.
- EITHER: (M1 4P2 or 4C2x2! or 5 x 4 OE (considering final 2 digits)
- M1 Mult by 4 or summing 4 options (considering first digit)
- A1) Correct final answer
- OR: (M1 Calculating total number of values (with subtraction seen)
- M1 Calculating number of unwanted values
- A1) Correct final answer
- EITHER: (M1 6 linked to considering middle digit e.g. multiplied or in list
- M1 Multiply an integer by 4 x 4 (condone x 16)
- A1) (No additional figures present for both M's to be awarded)
- OR: (M1 Calculating total number of values (with subtraction seen)
- M1 Calculating number of unwanted values
- A1) Correct final answer
- B1 252
- M1 Multiplying 2 combinations nCq x mCr, q + r = 5, or 9C5 seen alone
- M1 Summing 2 or 3 appropriate outcomes, involving perm/comb, no extra outcomes.
- A1 Total = 186 ways
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