Coplanar forces, of magnitudes F N, 3F N, G N and 50 N, act at a point P, as shown in the diagram. [Figure 6.1]
- (i)Given that F = 0, G = 75 and α = 60°, find the magnitude and direction of the resultant force.[4]
- (ii)Given instead that G = 0 and the forces are in equilibrium, find the values of F and α.[5]
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Mark scheme
Marking points from the official mark scheme (Oct/Nov 2017). The mark or mark type is shown in brackets.
- [M1] X = 75 + 50 cos 60 (= 100) Y = 50 sin 60 (= 43.3) For resolving forces (either direction)
- [A1] For both equations, unevaluated
- [B1] Resultant = √(100² + 43.3²) = 109 N
- [B1] Angle = arctan (43.3/100) = 23.4° Must state anticlockwise from the positive x-axis or show in a diagram
- [B1] 50 cos α - F cos 50 = 0 Resolving forces horizontally
- [B1] 50 sin α - 3F - F sin 50 = 0 Resolving forces vertically
- [M1] tan α = (3F + F sin 50) / (F cos 50) For division to find α or for using Pythagoras to find F
- [A1] α = 80.3
- [A1] F = 13.1
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