The equations of two lines l and m are r = 3i − j − 2k + λ(−i + j + 4k) and r = 4i + 4j – 3k + μ(2i + j − 2k) respectively.
- (i)Show that the lines do not intersect.[3]
- (ii)Calculate the acute angle between the directions of the lines.[3]
- (iii)Find the equation of the plane which passes through the point (3, -2, -1) and which is parallel to both l and m. Give your answer in the form ax + by + cz = d.[5]
Mark scheme
Marking points from the official mark scheme (Oct/Nov 2017). The mark or mark type is shown in brackets.
- [M1] (i) Equate at least two pairs of components of general points on l and m and solve for λ or for μ
- [A1] (i) Obtain correct answer for λ or μ, e.g. λ = 3 or μ = -2; λ = 0 or μ = -½; or λ = ⅔ or μ = -3/2
- [A1] (i) Verify that not all three pairs of equations are satisfied and that the lines fail to intersect
- [*M1] (ii) Carry out correct process for evaluating scalar product of direction vectors for l and m
- [DM1] (ii) Using the correct process for the moduli, divide the scalar product by the product of the moduli and evaluate the inverse cosine of the result
- [A1] (ii) Obtain answer 45° or ¼π (0.785) radians
- [(M1)] (iii) Attempt to calculate vector product of relevant vectors, e.g (-i+j+4k)×(2i + j - 2k)
- [A1] (iii) Obtain two correct components
- [A1] (iii) Obtain correct answer, e.g. -6i+6j-3k
- [M1] (iii) Substitute (3, -2, -1) in -6x+6y - 3z = d, or equivalent, and find d
- [A1)] (iii) Obtain answer -2x + 2y - z = −9, or equivalent
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