The diagram shows a triangle ABC in which A has coordinates (1, 3), B has coordinates (5, 11) and angle ABC is 90°. The point X (4, 4) lies on AC. Find [Figure 5]
- (i)the equation of BC,[3]
- (ii)the coordinates of C.[3]
This question uses a diagram from the original paper, which isn't shown here. Open the full paper from the past papers archive to see it.
Mark scheme
Marking points from the official mark scheme (Oct/Nov 2012). The mark or mark type is shown in brackets.
- [B1] Gradient of AB = 2
- [M1] Gradient of BC = -½ (using m₁m₂ = -1)
- [A1] Eqn of BC is y - 11 = -½(x - 5)
- [B1] gradient of AC (or AX) is ⅓
- [M1] Correct form of line equation + sim eqns (for AC using A or X)
- [A1] Sim equations → C(13, 7)
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