A-LevelMathematicsCoordinate geometry9709/12 · May/June 2015 · Q77 Marks
The point C lies on the perpendicular bisector of the line joining the points A (4, 6) and B (10, 2). C also lies on the line parallel to AB through (3, 11).
- (i)Find the equation of the perpendicular bisector of AB.[4]
- (ii)Calculate the coordinates of C.[3]
Mark scheme
Marking points from the official mark scheme (May/June 2015). The mark or mark type is shown in brackets.
- [B1] (i) M = (7, 4) co
- [B1] (i) m of AB = -2/3 co
- [M1 A1] (i) → y – 4 = (3/2)(x – 7) Use of m₁m₂ = -1 & their midpoint in the equation of a line. co
- [M1] (ii) Eqn of line parallel to AB through (3, 11) Needs to use m of AB
- [DM1A1] (ii) Sim eqns → C (9,7) Must be using their correct lines. Co
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