Sketch, on a single diagram, the graphs of y = 3e^-2x and y = secx for values of x such that 0 < x < π/2.
- (a)Sketch, on a single diagram, the graphs of y = 3e^-2x and y = secx for values of x such that 0 < x < π/2.[2]
- (b)Show that the x-coordinate of the point of intersection of the two graphs satisfies the equation x = ½ ln(3cosx).[2]
- (c)Use an iterative formula, based on the equation in part (b), to find the x-coordinate of the point of intersection correct to 3 decimal places. Give the result of each iteration to 5 decimal places.[3]
Mark scheme
Marking points from the official mark scheme (May/June 2025). The mark or mark type is shown in brackets.
- [B1] Sketch decreasing positive curve for y = 3e^-2x.
- [B1] Sketch curve for y = secx (Correctly placed with reference to first sketch or correct with '1' marked on y-axis).
- [M1] Equate and arrange at least as far as e^-2x =... or e^2x =... with cosx present.
- [A1] Confirm x = ½ ln(3cosx) (AG - necessary detail needed).
- [M1] Use iterative process correctly at least once (Calculator must be in radian mode).
- [A1] Obtain final answer 0.487 (Required to precisely 3 decimal places).
- [A1] Show sufficient iterations to justify answer, or show a sign change in the interval [0.4865, 0.4875] (Allow iterations to greater accuracy).
Write your answer and get it marked
On Oracle Prep you can write or photograph your own answer and have it marked by AI against this mark scheme, with feedback on what you missed.
Sign up free →