Let f(x) = (-7x²+2x-6)/((1+x)(4+x²))
- (a)Express f(x) in partial fractions.[5]
- (b)Hence find the exact value of ∫[from 0 to 2] f(x)dx. Give your answer in the form aπ-lnb, where a and b are constants.[6]
Mark scheme
Marking points from the official mark scheme (Feb/Mar 2025). The mark or mark type is shown in brackets.
- [B1] State or imply the form A/(1+x) + (Bx+C)/(4+x²)
- [M1] Use a correct method for finding a constant Even with incorrect PF denominators A(4+x²) + (Bx + C)(1 + x) + = −7x² +2x - 6
- [A1] Obtain one of A = −3, B = −4 and C = 6
- [A1] Obtain a second value
- [A1] Obtain a third value
- [B1 FT] Obtain term -3ln(1+x) OE FT A ln (1+x)
- [B1 FT] Obtain term -2ln(4+x²) OE FT B/2 ln (4+x²)
- [M1] Obtain integral of the form c tan⁻¹(x/d) with d ≠ 1 following separation into two expressions d = 2 or 2 only.
- [A1 FT] Obtain 3 tan⁻¹(x/2) FT C/2 tan⁻¹(x/2)
- [M1] Substitute correct limits correctly in an expression (obtained correctly) of the form aln(1+x), bln(4+x²), and ctan⁻¹(x/d), where a, b, c ≠ 0. a ln(3) + b ln(8) – b ln(4) + c(¼π), where a, b, c ≠ 0. Do not allow slips, and must get to c(¼π).
- [A1] Obtain answer ¾π - ln108 Must be in the form aπ – lnb.
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