The equations of two straight lines are r=i+j+2ak+λ(3i+4j+ak) and r=-3i-j+4k+μ(−i+2j+2k) where a is a constant.
- (a)Given that the acute angle between the directions of these lines is ¼π, find the possible values of a.[6]
- (b)Given instead that the lines intersect, find the value of a and the position vector of the point of intersection.[5]
Mark scheme
Marking points from the official mark scheme (May/June 2024). The mark or mark type is shown in brackets.
- [M1] Carry out correct process for evaluating the scalar product of direction vectors
- [M1] Using the correct process for the moduli, divide the scalar product by the product of the moduli and equate to ± √2/2
- [A1] State a correct equation in any form, e.g. (5+2a) / (√(25+a²)√9) = [±]√2/2
- [DM1] Form a quadratic equation in a with 3 or more terms all on one side and solve for a.
- [A2] Obtain a = 5 and a = 35
- [B1] Express general point of at least one line correctly in component form,
- [M1] Equate at least two pairs of corresponding components and solve for λ or μ or a
- [A1] Obtain λ = −1 or μ = −1
- [A1] Obtain a = 2
- [A1] Obtain position vector of the point of intersection is –2i – 3j + 2k
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