The complex numbers z and ω are defined by z = 1-i and ω =-3+3√3i.
- (a)Express zω in the form a + bi, where a and b are real and in exact surd form.[1]
- (b)Express z and ω in the form re^(iθ), where r > 0 and -π < θ < π. Give the exact values of r and θ in each case.[4]
- (c)On an Argand diagram, the points representing ω and zω are A and B respectively. Prove that OAB is an isosceles right-angled triangle, where O is the origin.[2]
- (d)Using your answers to part (b), prove that tan(π/12) = (√3+1)/(√3-1).[3]
This question uses a diagram from the original paper, which isn't shown here. Open the full paper from the past papers archive to see it.
Mark scheme
Marking points from the official mark scheme (May/June 2024). The mark or mark type is shown in brackets.
- [B1] State zω = (-3+3√3) + (3+3√3)i. Or exact equivalent with real and imaginary parts collected. Need brackets around the coefficient of i. Allow for a=, b= stated correctly.
- [B1] Obtain |z| = √2.
- [B1] Obtain arg z = -π/4 final answer.
- [B1] Obtain |ω| = 6.
- [B1] Obtain arg ω = 2π/3 final answer.
- [B1] Show |OA|=|AB| = 6, hence isosceles. One mark for ‘isosceles’ and one mark for 'right angle'.
- [B1] ∠AOB = arg ω - arg zω = -arg z = π/4 hence third angle is a right angle. There will be alternatives e.g. use of Pythagoras (ratio of lengths is 1:1:√2), expressing each number in “vector” form and using scalar product or explaining the effect of multiplying by 1 – i.
- [M1] Using your answers to part (b), prove that tan(π/12) = (√3+1)/(√3-1). For showing correct use of their angles from part (b). Must demonstrate where 5π/12 comes from.
- [M1] Correct method for their zω from part (a). Must link to point B on diagram or to arg zω. Need to see tan⁻¹((3+3√3)/(-3+3√3)) or tan θ = (3+3√3)/(-3+3√3) and not just tan⁻¹((1+√3)/(-1+√3)).
- [A1] Obtain given answer from full and correct working.
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