A smooth ring R of mass 0.2kg is threaded on a light string ARB. The ends of the string are attached to fixed points A and B with A vertically above B. The string is taut and angle ABR = 90°. The angle between the part AR of the string and the vertical is 60°. The ring is held in equilibrium by a force of magnitude XN, acting on the ring in a direction perpendicular to AR (see diagram).
- Calculate the tension in the string and the value of X.[5]
This question uses a diagram from the original paper, which isn't shown here. Open the full paper from the past papers archive to see it.
Mark scheme
Marking points from the official mark scheme (May/June 2023). The mark or mark type is shown in brackets.
- [M1] For attempt to resolve in one direction. Must use 0.2 substituted for m if just awarding M1 for vertical equation. Must have correct number of relevant terms (forces must have components as required). Allow sin/cos mix. Allow sign errors. Allow g missing.
- [A1] X sin 60 + T sin 30 - 0.2g = 0. OE. Correct vertical.
- [A1] X cos 60 - T - T cos 30 = 0. OE. Correct horizontal. If the two Ts are different, they can get max M1A1A0M0A0, unless they subsequently state that the two Ts are equal.
- [M1] For attempt to solve for tension or X. Must have correct number of relevant terms in both equations. Must get to 'T=' or ‘X='. Allow g missing. Can be implied by correct answers. If no working shown their values must follow from their equations.
- [A1] X = 2, tension in string = 0.536[N]. Allow exact value of tension = 4-2√3. Allow awrt 2.00 for X.
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