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A-LevelMathematicsAlgebra9709/12 · May/June 2023 · Q43 Marks

Solve the equation 8x⁶ + 215x³ – 27 = 0.

  1. Solve the equation 8x⁶ + 215x³ – 27 = 0.[3]

Mark scheme

Marking points from the official mark scheme (May/June 2023). The mark or mark type is shown in brackets.

  1. [M1] [8x⁶ + 215x³ – 27 = 0] leading to (8x³−1)(x³ +27)[= 0] OR -215±√(215²-4.8. – 27)/(2.8) or -215±√47089/2.8 OE If a substitution is used then the correct coefficients must be retained. Condone substitution of x = x³.
  2. [A1] 1/8, -27 Both correct values seen.
  3. [A1] 1/2 or 0.5, -3 SC: if M0 scored SCB1 is available for sight of 1/8 and -27 OE SC: if M0SCB1 scored then SCB1 is available for the correct answers and no others. Do not ISW if answers given as a range.

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About this question

Topic
Algebra, A-Level Mathematics (syllabus 9709). Structured question, 3 marks.
Source
A-Level Mathematics, May/June 2023 Paper 1 Variant 2, question 4.

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