The independent random variables X and Y have distributions Po(2) and B(20, ¹/₄) respectively.
- (a)Find the mean and standard deviation of X – 3Y.[5]
- (b)Find P(Y = 15X).[3]
Mark scheme
Marking points from the official mark scheme (May/June 2022). The mark or mark type is shown in brackets.
- [B1] E(Y) = 20 × ¹/₄ [= 5], Var(Y) = 20 × ¹/₄ × ³/₄ [= ¹⁵/₄ = 3.75] Both OE, SOI
- [B1] Var(X) = 2 SOI or standard deviation = √2
- [B1] E(X - 3Y) = 2 - 3 × 5 = -13
- [M1] Var(X - 3Y) = 2 + 9 × '¹⁵/₄' [= 35.75] Correct formula using their values
- [A1] Standard deviation of (X - 3Y) = 5.98 (3 s.f.) or √143/2 CWO
- [M1] (0, 0) and (1, 15)
- [M1] e⁻² × (2⁰/0!) × (²⁰C₀ × (¹/₄)⁰ × (³/₄)²⁰) + e⁻² × (2¹/1!) × (²⁰C₁₅ × (¹/₄)¹⁵ × (³/₄)⁵) Allow any λ. Poisson expressions must be seen
- [A1] 0.000430 (3 sf) CWO (must have evidence of addition) Allow 0.00043 or 4.3(0) × 10⁻⁴
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