The diagram shows a block of mass 10kg suspended below a horizontal ceiling by two strings AC and BC, of lengths 0.8 m and 0.6 m respectively, attached to fixed points on the ceiling. Angle ACB = 90°. There is a horizontal force of magnitude FN acting on the block. The block is in equilibrium. [Figure 4.1]
- (a)In the case where F = 20, find the tensions in each of the strings.[5]
- (b)Find the greatest value of F for which the block remains in equilibrium in the position shown.[3]
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Mark scheme
Marking points from the official mark scheme (May/June 2022). The mark or mark type is shown in brackets.
- [M1] Resolving horizontally or vertically
- [A1] TA × 0.8 - TB × 0.6 – 20 = 0
- [A1] TA × 0.6 + TB × 0.8 - 10g = 0
- [M1] Attempt to solve simultaneously
- [A1] TA = 76 N, TB = 68 N
- [B1] From using TB = 0
- [M1] TA × 0.8 - F = 0
- [A1] F = 400/3 [Allow F = 133 to 3 s.f.]
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