A curve has equation y = (9e^(2x) + 16) / (e^x - 1).
- (a)Show that the x-coordinate of any stationary point on the curve satisfies the equation e^x(3e^x – 8)(3e^x + 2) = 0.[4]
- (b)Hence show that the curve has only one stationary point and find its exact coordinates.[4]
Mark scheme
Marking points from the official mark scheme (May/June 2022). The mark or mark type is shown in brackets.
- [1] Use quotient rule (or equivalent) to find first derivative *M1 Condone poor use of brackets if recovered later
- [1] Obtain 18e^(2x)(e^x – 1) – e^x(9e^(2x) +16) / (e^x - 1)² OE
- [1] Equate first derivative to zero and attempt factorisation DM1 Need to be working with 9e^(3x) −18e^(2x) − 16e^x = 0
- [1] Obtain e^x(3e^x – 8)(3e^x + 2) = 0 AG – necessary detail needed SC B3 If numerator is in incorrect order and given result is obtained. SC B3 If denominator is not squared and given result is obtained.
- [1] Observe, using given result from part (a), at some stage, e^x ≠0 and 3e^x +2≠0 and hence one stationary point
- [1] Attempt exact solution for x and for y
- [1] Obtain x = ln(8/3) or exact equivalent
- [1] Obtain y = 48 Not from a rounded decimal
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