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A-LevelFurther MathematicsMatrices9231/12 · May/June 2010 · Q810 Marks

The matrix A is given by A = [[4, 1, -1], [-4, -1, 4], [0, -1, 5]].

  1. (a)Given that one eigenvector of A is [1, -2, -1]ᵀ, find the corresponding eigenvalue.[2]
  2. (b)Given also that another eigenvalue of A is 4, find a corresponding eigenvector.[2]
  3. (c)Given further that [1, -4, -1]ᵀ is an eigenvector of A, with corresponding eigenvalue 1, find matrices P and Q, together with a diagonal matrix D, such that A⁵ = PDQ.[6]

Mark scheme

Marking points from the official mark scheme (May/June 2010). The mark or mark type is shown in brackets.

  1. [1] (a) Multiply A by the given eigenvector: A[1, -2, -1]ᵀ = [[4, 1, -1], [-4, -1, 4], [0, -1, 5]] [1, -2, -1]ᵀ = [4(1)+1(-2)-1(-1), -4(1)-1(-2)+4(-1), 0(1)-1(-2)+5(-1)]ᵀ = [4-2+1, -4+2-4, 0+2-5]ᵀ = [3, -6, -3]ᵀ
  2. [1] (a) Observe A x = λx => [3, -6, -3]ᵀ = 3[1, -2, -1]ᵀ. So the eigenvalue λ = 3.
  3. [1] (b) Set up (A - λI)e = 0 for λ=4: (A - 4I)e = [[0, 1, -1], [-4, -5, 4], [0, -1, 1]]e = 0
  4. [1] (b) Solve (A - 4I)e = 0: From R3: -e₂ + e₃ = 0 => e₃ = e₂. From R1: e₂ - e₃ = 0 (consistent). From R2: -4e₁ - 5e₂ + 4e₃ = 0 => -4e₁ - 5e₂ + 4e₂ = 0 => -4e₁ - e₂ = 0 => e₂ = -4e₁. Let e₁ = t, then e₂ = -4t, e₃ = -4t. Choose t=0 (e.g. [0, 1, 1]ᵀ or multiple). The eigenvector is [0, 1, 1]ᵀ.
  5. [1] (c) Diagonal matrix D of eigenvalues: D = [[1, 0, 0], [0, 3, 0], [0, 0, 4]]. The order of eigenvalues must match the order of eigenvectors in P.
  6. [1] (c) Matrix P contains eigenvectors as columns: P = [[1, 1, 0], [-4, -2, 1], [-1, -1, 1]]. (Order must match D.)
  7. [1] (c) Matrix Q is the inverse of P: Q = P⁻¹
  8. [2] (c) Calculate P⁻¹: For any valid method (e.g., adj(P)/det(P)). P⁻¹ = [[-2/3, -1/2, 1/3], [-1/3, 1/2, 0], [0, 0, -1/3]]. (A2 for fully correct, A1 for one error)
  9. [1] (c) Conclusion about A⁵: A⁵ = PDP⁻¹.

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About this question

Topic
Matrices, A-Level Further Mathematics (syllabus 9231). Structured question, 10 marks.
Source
A-Level Further Mathematics, May/June 2010 Paper 1 Variant 2, question 8.

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