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A-LevelFurther MathematicsComplex numbers9231/12 · Oct/Nov 2017 · Q1012 Marks

Use de Moivre's theorem to show that sin 5θ = 5 sin θ – 20 sin³ θ + 16 sin⁵ θ.

  1. (i)Use de Moivre's theorem to show that sin 5θ = 5 sin θ – 20 sin³ θ + 16 sin⁵ θ.[5]
  2. (ii)Hence explain why the roots of the equation 16x⁴ – 20x² + 5 = 0 are x = ± sin(π/5) and x = ± sin(2π/5).[3]
  3. (iii)Without using a calculator, find the exact values of sin(π/5) sin(2π/5) sin(3π/5) sin(4π/5) and sin²(π/5) + sin²(2π/5).[4]

Mark scheme

Marking points from the official mark scheme (Oct/Nov 2017). The mark or mark type is shown in brackets.

  1. [1] B1 SOI
  2. [2] M1A1
  3. [1] M1
  4. [1] A1 AG
  5. [1] B1
  6. [1] B1
  7. [1] B1 AG
  8. [1] B1
  9. [2] M1A1
  10. [1] A1

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About this question

Topic
Complex numbers, A-Level Further Mathematics (syllabus 9231). Structured question, 12 marks.
Source
A-Level Further Mathematics, Oct/Nov 2017 Paper 1 Variant 2, question 10.

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