Prove by mathematical induction that, for z ≠ 1 and all positive integers n, 1 + z + z² + ... + zⁿ⁻¹ = (zⁿ - 1)/(z - 1)
- (i)Prove by mathematical induction that, for z ≠ 1 and all positive integers n, 1 + z + z² + ... + zⁿ⁻¹ = (zⁿ - 1)/(z - 1)[5]
- (ii)By letting z = ½(cos θ + i sin θ), use de Moivre's theorem to deduce that Σ∞ m=1 (½)ᵐ sin mθ = (2 sin θ)/(5 - 4 cos θ)[5]
Mark scheme
Marking points from the official mark scheme (May/June 2019). The mark or mark type is shown in brackets.
- [1] Shows base case.
- [1] States inductive hypothesis.
- [2] Combines fractions.
- [1] States conclusion.
- [1] States |z|<1 and uses formula for sum to infinity of geometric progression.
- [2] Uses de Moivre's theorem.
- [1] Multiply numerator and denominator by conjugate.
- [1] States imaginary part, AG.
Write your answer and get it marked
On Oracle Prep you can write or photograph your own answer and have it marked by AI against this mark scheme, with feedback on what you missed.
Sign up free →