O-LevelComputer ScienceAlgorithm design and problem-solving2210/22 · Oct/Nov 2023 · Q38 Marks
Four pseudocode statements and five pseudocode uses are shown.
- (a)Draw one line to link each pseudocode statement to the most appropriate pseudocode use. Not all pseudocode uses will be required. Pseudocode statement CALL Colour(NewColour) Value ← (A1 + A2 + A3) / 3 Loop1 ← Loop1 + 1 IF Count > 7 THEN X1 ← 0 Pseudocode use counting finding an average totalling using a conditional statement using a procedure[4]
- (b)A one-dimensional (1D) array called Temperatures[] has 25 elements beginning at index 1. It holds values that range between –20 and 100 inclusive. Write a pseudocode algorithm using a single loop to find the lowest value in this array and output the result only once. You do not need to declare or populate this array.[4]
Mark scheme
Marking points from the official mark scheme (Oct/Nov 2023). The mark or mark type is shown in brackets.
- [4] One mark for each correct line.
- CALL Colour (NewColour) -> using a procedure
- Value ← (A1 + A2 + A3) / 3 -> finding an average
- Loop1 ← Loop1 + 1 -> counting
- IF Count > 7 THEN X1 ← 0 -> using a conditional statement
- [4] One mark per mark point, max four
- MP1 initialise a variable to store the lowest number set to a high value (at least 100) / first value in the array
- MP2 loop structure to iterate 25 times
- MP3 use of IF to check if the array element is less than the current lowest value
- MP4 ...if it is, set this to the lowest value
- MP5 output the result (with an appropriate message) after the loop
- Example answer: Min ← 100 FOR Count ← 1 TO 25 IF Temperatures [Count] < Min THEN Min ← Temperatures [Count] ENDIF NEXT Count OUTPUT "The lowest temperature is ", Min
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