This question is about compound T, CₓH_yO₂. (a) Part of the mass spectrum of T is shown. The peak heights of the M and M+1 peaks are 33.9 and 3.4 respectively. [Figure: Mass spectrum of T]
- (a)(i)Calculate x, the number of carbon atoms present in T.[2]
- (a)(ii)Deduce the molecular formula of T.[1]
- (a)(iii)The mass spectrum has a peak at m/e = 119. Identify the fragment lost from T to produce this peak.[1]
- (b)The infra-red spectrum of T is shown. [Figure: IR spectrum of T with peaks V and W marked] Identify the type of bond responsible for each of the peaks V and W. Use the Data Booklet to help you. V W[1]
- (c)(i)Complete the table for the proton NMR spectrum of T. Use the Data Booklet to help you. δ/ppm type of proton 3.9 7.2–7.9[1]
- (c)(ii)The peak at δ = 2.4 ppm is due to a proton attached to a saturated carbon atom. State the two possible types of proton.[1]
- (c)(iii)Adding D₂O to T does not change its proton NMR spectrum. What does this tell you about the functional groups present in T?[1]
- (d)Use the information to draw two possible structures of T which are functional group isomers of each other.[2]
This question uses a diagram from the original paper, which isn't shown here. Open the full paper from the past papers archive to see it.
Mark scheme
Marking points from the official mark scheme (Feb/Mar 2017). The mark or mark type is shown in brackets.
- [1] n = 100 × (M+1)/(1.1 × M) = 100 × 3.4/(1.1 x 33.9) = 9.1
- [1] hence 9 carbons atoms
- [1] C9H10O2
- [1] (150-119=31), hence fragment is CH3O
- [1] V is C=O AND W is C-O
- [1] δ 3.9 is CH or alkyl/CH3 next to oxygen AND δ 7.2–7.9 is CH/aryl hydrogens
- [1] alkyl H next to C=O AND alkyl H next to aryl ring
- [1] none of the functional groups in T contains a labile proton/T does not contain –OH or –NH groups.
- [2] (Diagrams of methyl ethylbenzoate and ethyl methylbenzoate)
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