The compound Advantame is a sweetener that tastes approximately 25000 times sweeter than sucrose. [Figure: Structure of Advantame (C23H29NO4)]
- (a)Advantame is optically active. On the diagram of Advantame, circle all the chiral carbon atoms.[1]
- (b)(i)Suggest possible reagents and conditions for this decomposition.[1]
- (b)(ii)Name the type of reaction occurring.[1]
- (b)(iii)Draw the structure of L in the box above.[1]
- (c)(i)Aqueous bromine was added dropwise to a solution of J until the bromine was in excess. State what you would observe.[1]
- (c)(ii)J has the molecular formula C₁₄H₁₉O₆N. Use this formula to write an equation for the reaction of excess aqueous sodium hydroxide with one mole of J.[2]
- (d)(i)State what you would observe when an excess of aqueous bromine is added to a solution of K.[1]
- (d)(ii)K can be polymerised. Draw the structure of the polymer showing two repeat units. The linkage between the monomer units should be fully displayed.[2]
- (e)(i)State how many different carbon environments are present in K.[1]
- (e)(ii)The chemical shifts, δ, due to two of the carbon atoms x and y present in K are given in the table. carbon atom δ/ppm x 130 y 170 On the structure of K, circle and label two carbon atoms which could correspond to x and y.[1]
This question uses a diagram from the original paper, which isn't shown here. Open the full paper from the past papers archive to see it.
Mark scheme
Marking points from the official mark scheme (Feb/Mar 2017). The mark or mark type is shown in brackets.
- [1] two chiral carbon atoms correctly identified and circled on the diagram
- [1] H+(aq) + heat
- [1] hydrolysis
- [1] CH3OH (structure or formula)
- [1] white precipitate
- [2] C14H19O6N + 3NaOH → C14H16O6NNa3 + 3H2O
- [1] no change / colour remains orange
- [1] correct repeat unit showing amide linkage (-CO-NH-)
- [1] two repeat units shown (e.g. -[NH-CH(CH3)-CO]2-)
- [1] seven
- [1] x correctly identified as an aryl carbon (e.g., at 130 ppm) and y as the COOH carbon (at 170 ppm)
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