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A-LevelChemistryChemical energetics9701/12 · May/June 2012 · Q81 Mark

The value of the third ionisation energy of aluminium is 2740 kJ mol⁻¹. Which correctly represents this statement?

AAl(g) → Al³+(g) + 3e⁻ ∆H° = −2740 kJ mol⁻¹
BAl²+(g) → Al³+(g) + e⁻ ∆H° = −2740 kJ mol⁻¹
CAl(g) → Al³+(g) + 3e⁻ ∆H° = +2740 kJ mol⁻¹
DAl²+(g) → Al³+(g) + e⁻ ∆H° = +2740 kJ mol⁻¹

✓ Correct answer

D: Al²+(g) → Al³+(g) + e⁻ ∆H° = +2740 kJ mol⁻¹

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About this question

Topic
Chemical energetics, A-Level Chemistry (syllabus 9701). Multiple choice, 1 mark.
Source
A-Level Chemistry, May/June 2012 Paper 1 Variant 2, question 8.

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