State the reactants and conditions for two different types of reactions that both produce diethylamine, CH3CH2NHCH2CH3. reaction one .......................................................................................................... reaction two ..........................................................................................................
- (a)State the reactants and conditions for two different types of reactions that both produce diethylamine, CH3CH2NHCH2CH3. reaction one .......................................................................................................... reaction two ..........................................................................................................[4]
- (b)Describe the relative basicities of diethylamine, phenylamine and ammonia in aqueous solution. Explain your answer in terms of structure. least basic .......................................................................................................... explanation .......................................................................................................... most basic .......................................................................................................... explanation ..........................................................................................................[3]
- (c)Phenylamine reacts with HNO2(aq) at 4°C to form compound P. Compound P reacts with phenol under alkaline conditions at 4°C. The product of this reaction is acidified, forming azo compound Q. Draw the structure of compound Q. Circle the azo group on your structure. State one use of an azo compound such as Q. compound Q: [Figure for drawing box] An azo compound can be used ..........................................................................................................[2]
- (d)(i)CH3CH2NHCH2CH3 reacts with ethanoyl chloride, CH3COCl, to give the amide N,N-diethylethanamide, CH3CON(C2H5)2· An incomplete description of the mechanism of this reaction is shown in Fig. 9.1. box one Cl H3C-C=O H-N-C2H5 C2H5 reactants box two Cl H3C-C-O H intermediate N-C2H5 C2H5 Fig. 9.1 box three O H3C-C-N-C2H5 C2H5 and products Complete the mechanism in Fig. 9.1. You should include: • all relevant dipoles (δ+ and δ-) and full electric charges (+ and -) on the species in box one and in box two • all relevant lone pairs on the species in box one and in box two • all relevant curly arrows to show the movement of electron pairs in box one and in box two • the formula of the second product in box three.[4]
- (d)(ii)Name this mechanism.[1]
This question uses a diagram from the original paper, which isn't shown here. Open the full paper from the past papers archive to see it.
Mark scheme
Marking points from the official mark scheme (Oct/Nov 2023). The mark or mark type is shown in brackets.
- [1] (a) chloroethane and ethylamine
- [1] (a) heat, pressure, ethanol
- [1] (a) N-ethyl ethanamide CH3CONHC2H5
- [1] (a) LiAlH4
- [1] (b) phenylamine, ammonia, diethylamine
- [1] (b) Availability of lone pair on N to receive H+
- [1] (b) phenylamine – LP, delocalised / overlaps into ring
- [1] (b) diethylamine – ethyl are electron donating
- [1] (c) [diagram of azo dye]
- [1] (c) N2 or N=N circled AND dye / colouring
- [1] (d)(i) box one: dipole on C=O
- [1] (d)(i) LP on N of amine
- [1] (d)(i) CA from N of amine to C of acyl chloride
- [1] (d)(i) CA from = to O of acyl chloride
- [1] (d)(i) box two: + on what was N of amine and nowhere else
- [1] (d)(i) – on what was O of acyl chloride and nowhere else
- [1] (d)(i) LP on what was O of acyl chloride
- [1] (d)(i) CA from N-H bond to what was N of amine
- [1] (d)(i) CA from C-Cl bond to what was Cl of acyl chloride
- [1] (d)(i) CA from (LP on) O to reform C=O
- [1] (d)(i) box three: HCl
- [1] (d)(ii) Addition-elimination
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