A-LevelChemistryChemical energetics9701/12 · Oct/Nov 2017 · Q71 Mark
The following data are needed for this question. ∆Hᶠ (P4O10(s)) = −3012 kJ mol⁻¹ ∆Hᶠ (H2O(l)) = −286 kJ mol⁻¹ ∆Hᶠ (H3PO4(s)) = −1279 kJ mol⁻¹ What is ∆Hº for the reaction shown? P4O10(s) + 6H2O(l) → 4H3PO4(s)
A-9844 kJ mol⁻¹
B-388 kJ mol⁻¹
C-97 kJ mol⁻¹
D+2019 kJ mol⁻¹
✓ Correct answer
B: -388 kJ mol⁻¹
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